复数z1z2满足
复数z1,z2满足|z1|=|z1+z2|,z1'z2=a(1+√3i)复数z1,z2满足|z1|=|z1+z2|,z1拨*z2=a(1+√3i),其中a 是非零实数,求z2/z1
用z'表示z的共轭复数, z1'z2=a(1+√3i),其中a 是非零实数, ∴z1z2'=a(1-√3i),① ∴z1'z2+z1z2'=2a, 由|z1|=|z1+z2|,得 z1z1'=(z1+z2)(z1'+z2')=z1z1'+z1z2'+z1'z2+z2z2', ∴z2z2'=-2a,② ②/①,z2/z1=-2/(1-√3i)=-1/2-(√3/2)i.
答:设z1=a+hi z1+z2=-i--->z2=-z1-i=a-(+bi)-i=-a-(b+1)i |z1|=|z2|=1--->a^2+b^2=1,a^2+(...详情>>
答:详情>>