(d/dx)[∫dt/√(1+t^4)] =2x/√[1+(x^2)^4] =2x/√(1+x^8) 设y=y(x)是由方程e^x-e^y=sin(xy)所确定的隐函数，求微分dy e^x-e^y=sin(xy) ===> e^x-e^y*(dy/dx)=cos(xy)*[y+x*(dy/dx)] ===> e^x=cos(xy)y+xcos(xy)[dy/dx]+e^y*(dy/dx) ===> e^x-ycos(xy)=[xcos(xy)+e^y](dy/dx) ===> dy=[e^x-ycos(xy)]dx/[e^y+xcos(xy)]
答：第一题:求隐函数的导数:sin(xy)=x+y --->[sin(xy)]'=(x+y)' --->cos(xy)(xy)'=1+y' --->cos(xy)[...详情>>
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