求数学题解
若x2+y2-8x-10y+41=0 求X/y+y/x的值
x^2-8x+16+y^2-10y+25=0 (x-4)^2+(y-5)^2=0 得x-4=0 y-5=0 x=4 y=5 即4/5+5/4=16/20+25/20=41/20
解:x²+y²-8x-10y+41=0 即:x²-8x+16+y²-10x+25=0 (x-4)²+(y-5)²=0 所以:x-4=0,y-5=0 得:x=4,y=5 则:x/y+y/x =4/5+5/4 =41/20。
答:设y=A/x2 y=5 x=4 =>5=A/16 =>A=80 y=80/x2 x=5 y=80/25=16/5详情>>
答:详情>>