函数y=cos(π/2*x)*cos[π/2*(x-1)]的最小正周期?
函数y=cos(π/2*x)*cos[π/2*(x-1)]的最小正周期? 要过程
答案在附件里。
y=cos(pix/2)cos[(pi/2)(x-1)] =cos(pix/2)cos(-pi/2+pix/2) =cos(pix/2)[-sin(pix/2)] =(-1/2)sin(pix) 所以最小正周期T=2pi/(pi/2)=4.
函数y = cos(π/2*x)cos[π/2*(x-1)] = (1/2)cos[(π/2)(2x-1)] + (1/2)cos(π/2) = (1/2)cos[π(x-1/2)] 的最小正周期 T = (2π)/π = 2
答:澳洲的BIO-ISLAND宝宝顶级鳕鱼肝油详情>>
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