y=1/(x^2) x^(1/2)
由于存在根号，所以x大于零
y=1/(x^2) (1/4)*x^(1/2)) (1/4)*x^(1/2)) (1/4)*x^(1/2)) (1/4)*x^(1/2)
>=5*五次根号下(1/(x^2)*(1/4)*x^(1/2))*(1/4)*x^(1/2))*(1/4)*x^(1/2))*(1/4)*x^(1/2))
=5*（2的负五分之八次方）
当1/(x^2)＝(1/4)*x^(1/2)时取等号，即x＝2的负五分之四次方时有最小值5*（2的负五分之八次方），最大是正无穷大
问：求函数值域已知x属于R则函数y=根号(x^2+x+1)-根号(x^2-x+1)的值域为？
答：y=√[(x+1/2)²+(√3/2)²]-√[(x-1/2)²+(√3/2)²] 设p=(x+1/2,√3/2) q=...详情>>
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