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2018-05-21 04:24:06

• √2 / (1 i) = √2(1-i) / 2 = √2/2 - √2/2 i = cos(π/4) - i sin(π/4) = cos(-π/4)   i sin(-π/4) = e^(-π/4i)
  所以[√2 / (1 i) ]^3204 = e^(-π/4i) ^ 3204 = e^(-801πi) = e^(-πi) = cos(-π)   isin(-π) = -1

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  张***

  2018-05-21 04:24:06

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