分解因式(x^2 y^2
分解因式(x^2 y^2-2x 1)^2-(4y-4xy)(x^2-y^2-2x 1)分解因式(x^2+y^2-2x+1)^2-(4y-4xy)(x^2-y^2-2x+1) 求助,kkkkkkkk
(x^2+y^2-2x+1)^2-(4y-4xy)(x^2-y^2-2x+1) =(x^2+y^2-2x+1)^2-4y(1-x)(x^2-y^2-2x+1) =[(x-1)^2+y^2]^2+4y(x-1)[(x-1)^2-y^2] =[(x-1)^2+y^2]^2+4y(x-1)[(x-1)^2+y^2-2y^2] =[(x-1)^2+y^2]^2+2*2y(x-1)[(x-1)^2+y^2]+4y^2(x-1)^2 -4y^2(x-1)^2-8y^3(x-1) =[(x-1)^2+y^2+2y(x-1)]^2-4y^2(x-1)(x-1+2y) =[(x-1)(x-1+2y)+y^2]^2-4y^2(x-1)(x-1+2y) =[(x-1)(x-1+2y)]^2+2y^2(x-1)(x-1+2y)+y^4--4y^2(x-1)(x-1+2y) =[(x-1)(x-1+2y)]^2-2y^2(x-1)(x-1+2y)+y^4 =[(x-1)(x-1+2y)+y^2]^2 =[(x-1)^2+2y(x-1)+y^2]^2 ={[(x-1)+y]^2}^2 =(x+y-1)^4 。
(x^2+y^2-2x+1)^2-(4y-4xy)(x^2-y^2-2x+1) =(x^2+2xy-y^2-2x-2y+1)^2
答:别怕烦,全解出来,则原式变为:(用的方法是主元法,把X看成主元,把Y看成常数) (x+y-2xy)(x+y-2)+(xy-1)2=(y2-2y+1)x2-2(y...详情>>
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