初一数学代数式化简
(X+2Y)^4—(X+2Y)^2
(X+2Y)^4—(X+2Y)^2 =(X+2Y)^2[((X+2Y)^2-1] =(X+2Y)^2(X+2Y+1)(X+2Y-1)
(x+2y)^4-(x+2y)^2 =(x+2y)^2*(x+2y)^2-(x+2y)^2 然后把(x+2y)^2提一个出来 =(x+2y)^2[(x+2y)^2-1] =(x+2y)^2(x+2y+1)(x+2y-1)
是不是因式分解?如果是:则 (X+2Y)^4—(X+2Y)^2 =(x+2y)^2[(x+2y)^2-1] =(x+2y)^2(x+2y+1)(x+2y-1)
(X+2Y)^4—(X+2Y)^2 =(x+2y)^2*[(x+2y)^2-1] =(x+2y)^2*(x+2y+1)*(x+2y-1).
(X+2Y)^4—(X+2Y)^2 =(x+2y)²[(x+2y)²-1] =(x+2y)²(x²+4xy+4y²-1)
答:4-|2a-6|=4-(6-2a)=2a-2 2. -b^2+14ab+A=7a^2+4ab-2b^2 -2b^2+b^2+4ab+10ab+7a^2-7a^2...详情>>
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