2 題 Java 程式
可以把中間的Code ??出???
1. Complete the following definition of the static method OrderByCode that inputs an ArrayList items of MenuItems and returns a new ArrayList of MenuItems containing all the menu items (regardless of whether or not they are available) with all the appetizers listed first, all the entrees listed next, and all the desserts listed last.
Method:
public static ArrayList<MenuItem> OrderByCode( ArrayList<MenuItem> items )
{
...?
}
ArrayList<MenuItem> items = new ArrayList<MenuItem>();
d( new MenuItem( "Big Bad Burger", 9.95, 2.15, 1, true ) );
d( new MenuItem( "Cheeky Chicken", 5.95, 0.75, 1, true ) );
d( new MenuItem( "Wild Wings", 5.95, 0.50, 0, true ) );
d( new MenuItem( "Flying Fish", 15.95, 7.61, 1, false ) );
d( new MenuItem( "Igloo Icecream", 1.95, 0.28, 2, true ) );
ArrayList<MenuItem> ordered = OrderByCode( items );
for ( MenuItem item : ordered )
intln( nuString() );
Result: Wings, Burger, Chicken, Fish, Icecream ....
Hint: create a new ArrayList of MenuItems and add elements of the input to it, those with code 0 first, then those with code 1, and finally those with code 2. Finally, return the new ArrayList.
2. Complete the following definition of the static method AvailableItems that inputs an ArrayList items of MenuItems and returns a new ArrayList of MenuItems containing just those menu items that are currently available.
Method:
public static ArrayList<MenuItem> AvailableItems( ArrayList<MenuItem> items )
{
....?
}
ArrayList<MenuItem> items = new ArrayList<MenuItem>();
d( new MenuItem( "Big Bad Burger", 9.95, 2.15, 1, false ) );
d( new MenuItem( "Cheeky Chicken", 5.95, 0.75, 1, true ) );
d( new MenuItem( "Wild Wings", 5.95, 0.50, 0, false ) );
d( new MenuItem( "Flying Fish", 15.95, 7.61, 1, false ) );
d( new MenuItem( "Igloo Icecream", 1.95, 0.28, 2, true ) );
ArrayList<MenuItem> available = AvailableItems( items );
for ( MenuItem item : available )
intln( nuString() );
Result: Cheeky Chicken ($5.95) and Igloo Icecream ($1.95)......
Hint: Just create a new ArrayList of MenuItems and add elements of the input to it according as they're available or not. Then return the new ArrayList. Five lines of code max in the body of the method.
1。 public static ArrayList AvailableItems( ArrayList items )
{
ArrayList temp = new ArrayList();
for ( MenuItem item :items )
if (item。
Available())
d(new MenuItem(item。GetName(), item。GetPrice(), item。GetCost(),
item。GetCode(), item。
Available()));
return temp;
}
public static void main(String[] args) {
ArrayList items = new ArrayList();
d( new MenuItem( "Big Bad Burger", 9。
95, 2。15, 1, false ) );
d( new MenuItem( "Cheeky Chicken", 5。95, 0。75, 1, true ) );
d( new MenuItem( "Wild Wings", 5。
95, 0。50, 0, false ) );
d( new MenuItem( "Flying Fish", 15。95, 7。61, 1, false ) );
d( new MenuItem( "Igloo Icecream", 1。
95, 0。28, 2, true ) );
ArrayList available = AvailableItems( items );
for ( MenuItem item : available )
intln( nuString() );
}
}
2。
public static ArrayList OrderByCode( ArrayList items )
{
ArrayList temp = new ArrayList();
if ( Empty()) return temp;
//?]有說code的範??要找出minimum, maximum
int max= t(0)。
GetCode();
int min=max;
for ( MenuItem item : items )
{
int code =item。GetCode();
if (code > max) max=code;
if (code items = new ArrayList();
d( new MenuItem( "Big Bad Burger", 9。
95, 2。15, 1, true ) );
d( new MenuItem( "Cheeky Chicken", 5。95, 0。75, 1, true ) );
d( new MenuItem( "Wild Wings", 5。95, 0。
50, 0, true ) );
d( new MenuItem( "Flying Fish", 15。95, 7。61, 1, false ) );
d( new MenuItem( "Igloo Icecream", 1。95, 0。
28, 2, true ) );
ArrayList ordered = OrderByCode( items );
for ( MenuItem item : ordered )
intln( nuString() );
}
}
。
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