三角函数求值
cos40°(1+√3 tan10°)=? csc40°+cot80°=?
只做第2个 csc40°+cot80=1/sin40`+cos80`/sin80` =2cos40`/sin80``+cos80`/sin80` =(2cos40`+cos80`)/sin80` =(cos40`+cos40`+cos80`)/sin80 =[cos40+cos(60`-20`)+cos(60`+20`)]/sin80` `=(cos40`+2cos60`c0s20`)/sin80` =(cos40`+c0s20`)/sin80` =2cos30`c0s10`/sin80` =√3cos10`/sin80`=√3
原式=Cos40(2Sin30 Cos10+2Cos30 Sin10)/Cos10 =2Cos40 Sin40/Cos10 =Sin80/Cos10 =1 原式=1/sin40+sin10/cos10 =1/sin40cos10 (cos80+sin10sin40) =1/sin40cos10 (2sin40cos40+sin10sin40) =1/cos10 (2sin40+sin10) 夷居然做不出来,哎,最近变笨了。
csc40°+cot80°=cot20° 另一个做不出来,sorry啦
答:tan70cos10(3tan20-1) =cot20cos10(tan60tan20-1) =cot20cos10(sin60sin20-cos60cos20...详情>>
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