求导数
求y=sin(2x+sinπ/4)的导数,要过程,谢谢!
y=sin(2x+sin丌/4) ==> y=sin[2x+(根号2)/2],故y'=cos[2x+(根号2)/2]*[2x+(根号2)/2]'=2oos[2x+(根号2)/2]。
y′=[sin(2x+sinπ/4)]′=[cos(2x+sinπ/4)]*(2x+sinπ/4)′ =[cos(2x+sinπ/4)]*2 =2cos(2x+sinπ/4)
问:求导数求y=sin(2x+sinπ/4)的导数,要过程,谢谢!
答:y=sin(2x+sin丌/4) ==> y=sin[2x+(根号2)/2],故y'=cos[2x+(根号2)/2]*[2x+(根号2)/2]'=2oos[2x...详情>>
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