一道初二数学问题
分解因式: 有过程哦。新年快乐!
a+1+a(a+1)+a(a+1)^2+a(a+1)^3 =(a+1)[1+a+a(a+1)+a(a+1)^2] =(a+1)^2[1+a+a(a+1)] =(a+1)^3(1+a) =(a+1)^4
原式=(a+1)+a(a+1)+a(a+1)^2+a(a+1)^3 =(a+1)[1+a+a(a+1)+a(a+1)^2] =(a+1)^2[1+a+a(a+1)] =(a+1)^3(a+1) =(a+1)^4
答:a^2+b^2-c^2/2ab= sACB<1a^2+b^2-c^2/2ab<1a^2+b^2-c^2<2aba^2+b^2-c^2-2ab<0详情>>
答:详情>>