求极限
cos根号下x+1减去cos根号下x的趋向于正无穷的极限是多少?
cos根号下x+1减去cos根号下x的趋向于正无穷的极限是多少? lim[cos√(x+1)-cos√x] =lim(-2)*sin{[√(x+1)+√x]/2}*sin{[√(x+1)-√x]/2} =lim(-2)*sin{[√(x+1)+√x]/2}*sin{(1/2)*1/[√x+1+√x] 很显然=lim1/[√x+1+√x]=0 所以,limsin{(1/2)*1/[√x+1+√x]=0 而,sin{[√(x+1)+√x]/2}有界 所以,上述极限为零
问:数学题根号下(1+(根号下(x+根号下x)))-1(x趋向于0)与mx^n是等价无穷小,求m,n.
答:解:lim√{1+[√(x+√x)]}-1/mx^n =lim(1/2)[√(x+√x)]/mx^n =lim(1/2)[√(√x+1)]/mx^(n-1/4)...详情>>
答:详情>>