高一计算
答案a的2/3次方
解: 设a的1/3次方=x,b的1/3次方=y 原式=[(x^4-8xy^3)/(x^2+2xy+4y^2)]÷ (1-2y/x) =[(x^4-8xy^3)/(x^2+2xy+4y^2)]÷ [(x-2y)/x] =[(x^4-8xy^3)/(x^2+2xy+4y^2)]×[x/(x-2y)] =x(x^4-8xy^3)/[(x^2+2xy+4y^2)(x-2y)] =x^2(x^3-8y^3)/(x^3-8y^3) =x^2 =a的2/3次方
答:(1+2的-1/32次方)*(1+2的-1/16次方)*(1+2的-1/8次方)*(1+2的-1/4次方)(1+2的-1/2次方)= {[(1+2的-1/32次...详情>>
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