高一数学 化简
sinA分之sin(2A+B)-2cos(A+B)
sin(2A+B)/sinA-2cos(A+B) =【sinAcos(A+B)+cosAsin(A+B)】/sinA-2cos(A+B) =cos(A+B)+cosAsin(A+B)/sinA-2cos(A+B) =cosAsin(A+B)/sinA-cos(A+B) =【cosAsin(A+B)-sinAcoa(A+B)】/sinA =-【sinAcoa(A+B)-cosAsin(A+B) 】/sinA =-sin(A-A-B)/sinA =sinB/sinA
答:sin(α+β)cosα-1/2[sin(2α+β)-sinβ] =sinαcosβcosα+sinβcosαcosα-1/2[sin2αcosβ+sinβco...详情>>
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