解不等式 (x^2-3|x-3|)/(x^2-x-2)≥2
≤|≥(附加符号,解题使用)谢谢!
(x^2-3|x-3|)/(x^2-x-2)≥2 x>=3时 [x^2-3x+9-2x^2+2x+4]/(x-2)(x+1)≥0 (x^2+x-13)/(x-2)(x+1)≤0 3≤x≤(-1+√53)/2 x<3时 [x^2+3x-9-2x^2+2x+4]/(x-2)(x+1)≥0 (x^2-5x+5)/(x-2)(x+1)≤0 -1
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答:解: [(x-3)/2]+3>x+1 --->x-3+6>2x+2 --->x<1; 1-3(x-1)=<8-x --->1-3x+3=<8-x --->2x>...详情>>
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