已知1x1y=3
已知:1/x-1/y=3,求代数式(2x²yz+z²)/(x²-2xy+z²)的值已知:1/x-1/y=3,求代数式(2x²yz+z²)/(x²-2xy+z²)的值
1/x-1/y=3,y-x=3xy. (3x+xy-3y)/(x-xy-y)=(-9xy+xy)/(-3xy-xy)=2
答:已知1/X-1/Y=3则代数式(2X-14XY-2Y)/(X-2XY-Y)的值为 已知:1/x-1/y=3 所以:1/x-1/y=(y-x)/(xy)=3 即:...详情>>
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