直线L1：y=kx；代入y^2=2px，得：A(2p/k^2,2p/k) 直线L2：y=-x/k；代入y^2=2px，得：B(2pk^2,-2pk) AB斜率 = k/(1 -k^2) AB方程：y-(-2pk) = [k/(1+k^2)]*[x-(2pk^2)] ...(1) 过原点垂直AB的直线的方程：y =[-(1 -k^2)/k]x ...(2) (1)(2)消去k，得点M的坐标的轨迹方程：x^2 +y^2 -2px = 0
答：顶点(2n+1/2n(n+1),-1/4n(n+1)) 顶点设为(x,y) 即x=2n+1/2n(n+1) y=-1/4n(n+1) (n为参数) 消...详情>>
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