若x的三次方+5x的平方+3x+m有因式x
若x的三次方+5x的平方+3x+m有因式x-1,求m的值,并将原式因式分解。谢谢大家!
m的值为待求,通常用长除法,除得余式为m+9,商为(x2+6x+9)由题意x的三次方+5x的平方+3x+m有因式x-1即能整除,故m+9=0,所以m=-9 x3+5x2+3x-9=(x-1)(x2+6x+9)=(x-1)(x+3)(x-3)
x*x*x-x*x+6x*x-6x+9x-9=(x-1)(x*x+6x+9)=(x-1)*(x+3)*(x+3) m=-9
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