有力的出力啊!!!!!!!!!!!!
求值:sin50°(1+√3tan10°)
sin50°(1+√3tan10°) =sin50°(cos10°+√3sin10°)/cos10° =2sin50°[(1/2)cos10°+(√3/2)sin10°]/cos10° =2sin50°[cos60°cos10°+sin60°sin10°]/cos10° =2sin50°cos50°/cos10° =sin100°/cos10° =cos10°/cos10° =1 要写全啊
sin50°(cos10+sin10)/cos10 2(1/2cos10+√3/sin10)/cos10 2sin40cos40/cos10 sin80/cos10 cos10/sin10 1
解: sin50°(1+√3tan10°) =sin50°(cos10°+√3sin10°)/cos10° =2sin50°[(1/2)cos10°+(√3/2)sin10°]/cos10° = 2sin50°sin40°/cos10=2sin50°sin40°/sin80° =sin50°/c0s40°=1
你这种学生有点耍小聪明,这么简单的题目都不自己做,真懒!!!
答:这样的孩子应该都是农村的了,城里的孩子现在都是爷……详情>>