7^24-1=(7^12+1)(7^12-1)=(7^12+1)(7^6+1)(7^6-1)=(7^12+1)(7^6+1)(7^2-1)(7^4+7^2+1),7^2-1=48,即7^24-1是48的倍数 又7^24-1=(7^12+1)(7^12-1)=(7^12+1)(7^6+1)(7^6-1)=(7^12+1)(7^6+1)(7^3+1)(7^3-1),7^3+1=(7+1)(7^2-7+1)=8*43,即7^24-1是43的倍数
7^24-1 =(7^12+1)(7^12-1) =(7^12+1)(7^6+1)(7^6-1) =(7^12+1)(7^6+1)(7^3+1)(7^3-1) =(7^12+1)(7^6+1)*344*(7^3-1) =(7^12+1)(7^6+1)*43*8*(7^3-1) 7^24-1 =(7^8-1)(7^16+7^8+1) =(7^4+1)(7^4-1)(7^16+7^8+1) =(7^4+1)(7^2+1)(7^2-1)(7^16+7^8+1) =(7^4+1)*50*48*(7^16+7^8+1)
7^24-1=(7^12)^2-1=(7^12+1)(7^12-1) =(7^12+1)(7^6+1)(7^6-1) =(7^12+1)(7^6+1)(7^3+1)(7^3-1) =(7^12+1)(7^6+1)[(7+1)(7^2-7*1+1)][(7-1)(7^2+7*1+1)] =(7^12+1)(7^6+1)*48*43*57. ∴7^24-1可被40至50之间的两个整数整除，这两个整数就是 43，48.
答：这两个数是：63和65。 (2^48-1)÷63=4467856773185 (2^48-1)÷65=4330384257087 要知道理由吗？ 因为63=(2...详情>>
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