已知a + 1
已知a + 1/a = 5 求: a4/a2 + a2 + 1的值
此题有误,应为:已知a + 1/a = 5 求: a2/a4+ a2 + 1的值 解;a + 1/a = 5 (a + 1/a )^2=25 a^2/a^4 + a^2 +2=25 a^2/a^4+ a^2 =23 a^2/a^4 + a^2 +1 =24
a + 1/a = 5 (*a) a^2 + 1 = 5a a^2 = 5a-1 a^4/a^2 + a^2 +1 = 0 a^(4-2) + a^2 + 1 = 0 2 a^2 + 1 = 0 , (a^2 = 5a-1) 2(5a - 1) + 1 = 0 10a - 2 + 1 = 0 10a - 1 = 0 10a = 1 a = 1/10
a4/a2 + a2 + 1 看不懂 分子,分母各是什么,没有括号,看不明白
答:解:a+1/a=5,则(a+1/a)^2=5^2,a^2+1/a^2=23. (a^4+a^2+1)/a^2………………(分式的分子与分母同除以a^2) =(a...详情>>
答:1.a^3-a^2-a+1 =(a^3+1)-(a^2+a) =(a+1)(a^2-a+1)-a(a+1) =(a+1)(a^2-a+1-a) =(a+1)(a...详情>>