一道容易的分解因式 急用
要过程
解:原式=(x^2+1)^2-(2x)^2 =(x^2+2x+1)(x^2-2x+1) =(x+1)^2*(x-1)^2 =[(x+1)(x-1)]^2 =(x^2-1)^2
解:原式=(x^2+1^2)^2-(2x)^2 =(x^2+1+2x)(x^2+1-2x) =(x^2+2x+1)(x^2-2x+1) =(x+1)^2*(x-1)^2 =[(x+1)(x-1)]^2
解:原式=(x^2+1^2)^2-(2x)^2 =(x^2+1+2x)(x^2+1-2x) =(x^2+2x+1)(x^2-2x+1) =(x+1)^2*(x-1)^2 =[(x+1)(x-1)]^2
答:a^2(x-y)+b^2(y-x) =a^2(x-y)-b^2(x-y) =(x-y)*(a^2-b^2) =(x-y)*(a+b)*(a-b)详情>>