高一数学
求方程2x^3+3x-3=0的一个实数解。精确到0.01
精确解: 1/2*(6+2*11^(1/2))^(1/3)-1/(6+2*11^(1/2))^(1/3) -1/4*(6+2*11^(1/2))^(1/3)+1/2/(6+2*11^(1/2))^(1/3)+1/2*i*3^(1/2)*(1/2*(6+2*11^(1/2))^(1/3)+1/(6+2*11^(1/2))^(1/3)) -1/4*(6+2*11^(1/2))^(1/3)+1/2/(6+2*11^(1/2))^(1/3)-1/2*i*3^(1/2)*(1/2*(6+2*11^(1/2))^(1/3)+1/(6+2*11^(1/2))^(1/3)) 数字解: -0.3676 + 1.3803i -0.3676 - 1.3803i 0.7351
问:实数~急~4√ ̄(2)+2三次根号下-5-1/3√ ̄(3) (精确到0.01)
答:1.659552087≈1.66详情>>
答:详情>>