{[(a²-5a+2)/(a+2)]+1}÷[(a²-4)/(a²+4a+4)]
=[(a-2)²/(a+2)]×{(a+2)²/[(a-2)(a+2)]}
=a-2=2+√3-2=√3.
试着写一下，因为不能完全确定分子分母！
{[(a^2-5a+2)/(a+2)]+1}÷[(a^2-4)/(a^2+4a+4)]
=[(a^2-5a+2+a+2)/(a+2)]×[(a^2+4a+4)/(a^2-4)]
=[(a^2-4a+4)/(a+2)]×[(a^2+4a+4)/(a^2-4)]
=[(a-2)^2/(a+2)]×[(a+2)^2/(a+2)*(a-2)]
=a-2
=(2+√3)-2
=√3.
答：(a^2+3a)/(a^2+4a+4)÷(a+3)/(a+2)-2/(a+2),其中a=(√2)-2 解:(a^2+3a)/(a^2+4a+4)÷(a+3)/(...详情>>
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