根式计算(7)
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解:把-(3+√2)x拆成-x-(2+√2)x=-x-√2(1+√2)x (1+√2)x^2-(3+√2)x+√2=0 (1+√2)x^2-√2(1+√2)x-x+√2=0 (1+√2)x(x-√2)-(x-√2)=0 (x-√2)[(1+√2)x-1]=0 所以 (x-√2)=0 或 [(1+√2)x-1]=0 即x1=√2 或x2=1/(1+√2)=(√2-1)/[(1+√2)(√2-1)]=√2-1
答:1.若│1995-a│+√a-2000=a,求a-(1995平方) 的值 a-2000>=0, a>=2000 1995-a<0 -(1995-a)+√a-2...详情>>
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