计算
4a2b 5c2d 2abc ---- . ---- 除 ----- 3cd2 4ab2 3d
题目是(4a^2b)/(3cd^2)*(5c^2d)/(4ab^2)÷((2abc)/(3d))吧? 若是,则 =(5ac)/(3bd)/((2abc)/(3d)) =(5ac)/(3bd)*((3d)/(2abc)) = 5/(2b^2)
[(4a²b)/(3c²d)]×[(5c²d)/(4ab²)]÷[(2abc)/(3d)] = [(4a²b)(5c²d)(3d)]/[(3c²d)(4ab²)(2abc)] = (3*4*5a²bc²d²)/(2*3*4a²b³c³d) = (5d)/(2b²c)
答:a和a乘,先把4乘以-3等于-12,次方相加就是a的五次方,那就是-12a的五次方,后面x一样,b的七次方,所以答案就是-12a的五次方bx的七次方详情>>
答:详情>>