已知sin(x+π
已知sin(x+π/6)=1/4,求sin(7π/6+x)+cos^2(5π/6-x)的值已知sin(x+π/6)=1/4,求sin(7π/6+x)+cos^2(5π/6-x)的值
因为sin(x+π/6)=1/4,所以sin(7π/6+x)=sin(π+π/6+x)=-sin(x+π/6)=-1/4,cos^(5π/6-x)=cos^(π-(π/6+x))=cos^(x+π/6)=1-sin^(x+π/6)=1-/16=15/ n(7π/6+x)+cos^2(5π/6-x)=-1/4+15/16=11/16
答:已知sin(x+兀/6)=1/4,求sin[(7/6)兀+x)]+cos^2[(5/6)兀-x]的值 已知sin(x+π/6)=1/4,所以: sin[x+(7...详情>>