一道数学拓展题,请问何方法最快解答
(1 121*1 212)/( 2121* 2212)=?
原式 = [(121*1001001001)*(12*10101010101)]/[(21*10101010101)*(212*1001001001)] = (121*12)/(21*212) = 121/371
121121121121=121121*1000001=121*1001*1000001 121212121212=121212*1000001=12*10101*1000001 212121212121=212121*1000001=21*10101*1000001 212212212212=212212*1000001=212*1001*1000001 原式=121*12/(21*212)
121121121121=1001001001*121 121212121212=10101010101*12 212121212121=10101010101*21 212212212212=1001001001*212 消去前面的,后面的作乘除就可以了
答:123456,12345678试了没?详情>>
答:详情>>