数学题目请高手或者老师帮忙,要有步骤,感谢您1
|e1|=|e2|=1, e1•e2=0 a=-(2e1+e2),b=e1-λe2 --->a•b = (-2e1-e2)•(e1-λe2) = -2|e1|²+(λ-2)e1•e2+λ|e2|² = λ-2 (1)a∥b--->-2:1 = (-1):(-λ)--->λ=-1/2 (2)a⊥b--->a•b = λ-2 = 0------>λ=2
(1)a//b a=kb -(2e1+e2)=k(e1-λe2) -2e1=ke1 k=-2 -1e2=-kλe2 λ=-1/2 (2)ab,a*b=0,-(2e1+e2)*(e1-λe2)=0
答:详情>>