请教:异分母加减五年级计算。
1又1/4-9/20+11/30-13/42+15/56 要求简算
首先看:首先看:9/20 =1/4 +1/5 11/30 =1/5 +1/6 13/42 =1/6 +1/7 15/56 =1/7 +1/8 原式=1+1/4-(1/4+1/5)+1/5+1/6-(1/6+1/7)+1/7+1/8 =1+1/4-1/4-1/5+1/5+1/6-1/6-1/7+1/7+1/8 =1+1/8 =1又1/8 我打出来的分数在这里不认可,只能这样了,不知道你是否看得明白。
1又1/4-9/20+11/30-13/42+15/56=(1+1/4)-[(4+5)/(4×5)]+[(5+6)/(5×6)]-[(6+7)/(6×7)+[(7+8)/(7×8)]=(1+1/4)-(1/4+1/5)+(1/5+1/6)-(1/6+1/7)+(1/7+1/8)=1+(1/8)=9/8(或化为带分数:"1又1/8")。
1又1/4-9/20+11/30-13/42+15/56 =5/4-9/20+11/30-13/42+15/56 =5/4-(1/4+1/5)+(1/5+1/6)-(1/6+1/7)+(1/7+1/8) =5/4-1/4-1/5+1/5+1/6-1/6-1/7+1/7+1/8 =(5/4-1/4)+(1/5-1/5)+(1/6-1/6)+(1/7-1/7)+1/8 =1+1/8 =9/8
太麻烦了!!!!!!!!!!!!
答:5/4-9/20+11/30-13/42+15/56-17/72+19/90 =(1+1/4)-(1/4+1/5)+(1/5+1/6)-(1/6+1/7)+(1...详情>>
答:详情>>