c语言的程序填空题？
1. 下列程序的功能是创建单向链表。
#include <stdio.h>
#include <alloc.h>
struct link {
char name[10];
int mark;
struct link * next;
};
void insert(char *, int);
struct link * head = NULL;
main()
{
char name[10];
int mark;
struct link * t;
while ( 1 ) {
scanf("%s %d", name, &mark);
if ( strcmp(name, "#") == 0 ) break;
______(1)_______;
}
for (t=head; ______(2)_______)
printf("<%s>: %d\n", t->name, t->mark);
}
void insert(char * name, int mark)
{
struct link * p;
p = ______(3)_______ ;
strcpy(p->name, name);
p->mark = mark;
______(4)_______;
if ( head != NULL ) ______(5)_______;
head = p;
}
2. prog.c是带命令行参数的程序。运行prog filename时，将文本文件filename中的内容原样输出；运行prog -u filename时，将文本文件filename中的所有字母以大写方式输出（其余字符原样输出）；运行prog -d filename时，只将文本文件filename中的数字输出。
# include <stdio.h>
# include <ctype.h>
void main(int argc, char * argv[])
{
FILE *fp;
char * filename, ch;
int tag=0;
if (argc <2 || argc>3) { printf(“Argument error\n”); return; }
if (argc == 3) {
if (strcmp(argv[1], “-u”) == 0) tag=1;
else if (strcmp(argv[1], “-d”) == 0) tag=2;
else {printf(“Option error\n”); return;}
______(6)_______;
}
else filename = argv[1];
if (______(7)_______) {
printf(“Cannot open file\n”); return;
}
while (______(8)_______ ) {
ch = fgetc(fp);
if ( tag == 0 ) putchar(ch);
else if ( tag == 1 ) ______(9)_______;
else if ( ______(10)_______) putchar(ch);
}
fclose(fp);
}
#include
#include
#include
struct link {
char name[10];
int mark;
struct link * next;
};
void insert(char *, int);
struct link *head=NULL;
void main()
{
char name[10];
int mark;
struct link * t;
while (1) {
scanf("%s %d", name, &mark);
if(strcmp(name, "#") == 0 ) break;
insert(name,mark);
}
for (t=head;t!=NULL;t=t->next)
printf(": %d\n", t->name, t->mark);
}
void insert(char * name, int mark)
{
struct link *p;
p=(struct link *)malloc(sizeof(struct link));
strcpy(p->name,name);
p->mark=mark;
p->next=NULL;
if(head != NULL) p->next=head;
head=p;
}
/***************************/
# include
# include
# include
void main(int argc, char * argv[])
{
FILE *fp;
char * filename, ch;
int tag=0;
if (argc 3) { printf("Argument error\n"); return; }
if (argc == 3) {
if (strcmp(argv[1], "-u") == 0) tag=1;
else if (strcmp(argv[1], "-d") == 0) tag=2;
else {printf("Option error\n"); return;}
filename=argv[2];
}
else filename = argv[1];
if ((fp=fopen(filename,"r"))==NULL) {
printf("Cannot open file\n"); return;
}
while (!feof(fp)) {
ch = fgetc(fp);
if ( tag == 0 ) putchar(ch);
else if ( tag == 1 ) putchar(toupper(ch));
else if (ch>='0' &&ch<='9') putchar(ch);
}
fclose(fp);
}
。
答案 1)insert(name,mark) 2)t!=NULL;t=t->next 3)new struct link 4)p->next=NULL 5)p->next=head 6)filename = argv[2] 7)(fp=fopen(filename, "r"))==NULL 8)!feof(fp) 9)putchar(toupper(ch)) 10)ch>='0' && ch<='9'
(1)insert(name,mark) (2)t!=NULL;t=t->next (3)new struct link (4)p->next=NULL (5)p->next=head (6)filename = argv[2] (7)(fp=fopen(filename, "r"))==NULL (8)!feof(fp) (9)putchar(toupper(ch)) (10)ch>='0' && ch<='9'
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